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Electronics

Ohm's law explained

Ohm's law says the current through a resistor is proportional to the voltage across it: V = I × R. Voltage (V, in volts) is the push, current (I, in amps) is the flow, and resistance (R, in ohms) is the squeeze. Know any two and the third follows.

The rule

V = I × R

Rearrange it for whichever one you're missing:

  • I = V over R: current from voltage and resistance
  • R = V over I: resistance from voltage and current

More push, more flow. More squeeze, less flow. Double the voltage across the same resistor and the current doubles, so a graph of current against voltage is a straight line. Georg Ohm published that in 1827, and the rule carries his name.

Live experiment

Three dials, one law

A battery and a resistor in a loop, with a current meter. Set any two of push (V), flow (I) and squeeze (R) and the third works itself out. Then try the three goals underneath.

Try it yourself: free lesson

“Ohm's law” is lesson 5 of 6 in Copper Flats, Electronics World 1. Free with an account. Lessons unlock in order, so you’ll do the 4 before it first.

A worked example

A 9 V battery is connected across a 1 kΩ resistor. What current flows?

I = 9 V over 1000 Ω = 0.009 A = 9 mA

Sizing an LED resistor

The most common use of Ohm's law at a workbench is picking the resistor for an LED. The LED keeps a roughly fixed forward voltage for itself, and the resistor takes whatever is left:

R = Vsupply − VLED over I

Take 5 V from USB, a red LED that drops about 2.0 V, and a target of 15 mA:

R = 5 − 2.0 over 0.015 = 200 Ω

200 Ω isn't in the common E12 range, so round up to the next value that is: 220 Ω gives about 13.6 mA. Rounding up keeps the current safely below your target.

Where it applies

Ohm's law describes resistors and wires very well. It doesn't describe everything: an LED's current isn't proportional to its voltage, and neither is a diode's. That's why you apply the law to the resistor and treat the LED's forward voltage as a fixed drop.

It also connects to power. Combine V = I × R with P = V × I and you get P = I² × R, which tells you how hot a resistor runs. That's the next thing to check once you've picked a value.

Free lesson

Now build it yourself

Each lesson comes in three short parts: see the idea, try it on a live board, then build it yourself, with quick checks as you go.

Try it yourself: free lesson

“Ohm's law” is lesson 5 of 6 in Copper Flats, Electronics World 1. Free with an account. Lessons unlock in order, so you’ll do the 4 before it first.

Or start from the very first lesson, no account needed

Work it out

Practice questions

Three quick questions from the lessons. Pick an answer to check it.

  1. Question 1 of 3Same resistor, but a stronger battery. The current…
    Show the answer

    Answer: Gets bigger. More push through the same squeeze means more flow. A stronger battery drives more current through the same resistor.

    • Why not “Stays the same”? By Ohm's law, I = V ÷ R. With R fixed, raising V raises I in proportion.
    • Why not “Gets smaller”? Current falls when the resistance goes up or the voltage goes down. A stronger battery is more voltage, which drives more current.
    • Why not “Stops”? Current stops only when the loop is broken. A stronger battery pushes harder, so more current flows, not none.
  2. Question 2 of 3Why does an LED need a series resistor?
    Show the answer

    Answer: To limit the current. Once an LED is on, a tiny rise in voltage causes a huge rise in current. The resistor sets a safe current.

    • Why not “To store charge”? Storing charge is a capacitor's job. A resistor stores nothing: it turns some energy into heat as it limits the current.
    • Why not “It doesn't need one”? Without one, an LED on a battery draws far too much current and burns out, because its current rises steeply with a small rise in voltage.
    • Why not “To change its colour”? An LED's colour is set by the material it's made from. A resistor changes how much current flows, not the colour of the light.
  3. Question 3 of 3If you double the current through a resistor, its power is multiplied by…
    Show the answer

    Answer: 4. P = I² × R. Doubling I multiplies I² by 4.

    • Why not “It doesn't change”? The resistance stays the same, but the power doesn't: P = I² × R, so doubling I multiplies P by four.
    • Why not “½”? More current means more power, never less. With the same resistor, P = I² × R grows four times when I doubles.
    • Why not “2”? Power goes with the square of the current, P = I² × R, so twice the current gives 2² = 4 times the power, not twice.
Keep practising: free lesson

“Ohm's law” is lesson 5 of 6 in Copper Flats, Electronics World 1. Free with an account. Lessons unlock in order, so you’ll do the 4 before it first.

Questions people ask

What is Ohm's law in simple terms?

The current through a resistor is proportional to the voltage across it. Written out, V = I × R: voltage equals current times resistance. Know any two of the three and you can work out the third.

How do you find current with Ohm's law?

Divide the voltage by the resistance: I = V ÷ R. A 9 V battery across 1 kΩ gives 9 ÷ 1000 = 0.009 A, which is 9 mA. Volts divided by kilohms give milliamps directly.

Does Ohm's law work for LEDs?

Not directly. An LED's current isn't proportional to its voltage: it keeps a roughly fixed forward voltage, about 2 V for a red LED. Apply Ohm's law to the resistor in series with it, using the voltage that's left over.

Who discovered Ohm's law?

Georg Ohm, a German physicist, published it in 1827 after measuring how the current changed as he changed the length of wire in the circuit.

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