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Signals & Wireless (RF)

How an LC band-pass filter picks one station

A series LC band-pass filter is a coil and a capacitor placed one after the other in a signal's path. At one frequency their reactances are equal and opposite and cancel, so the pair acts like a plain wire and that frequency passes. Below it the capacitor blocks; above it the coil does. That's how a simple radio picks one station out of everything an antenna hears.

Opposite reactances

Each part holds back AC by its reactance, in ohms, and it changes with frequency. A coil's rises; a capacitor's falls:

XL = 2π f L XC = 1 over 2π f C

They also act in opposite directions, so they're written with opposite signs: +j for the coil, −j for the capacitor. At 10 MHz a 2.5 µH coil is +j157 Ω and a 100 pF capacitor −j159 Ω. In series they add to about 2 Ω: next to nothing.

Find the capacitor

They cancel where XL = XC, at the resonant frequency:

f = 1 over 2π √(L C) so C = 1 over 4π² f² L

For 10 MHz and 2.5 µH, C = 1 ÷ (4π² × 10¹⁴ × 2.5 × 10⁻⁶) ≈ 100 pF.

What gets through

With a 50 Ω receiver, the fraction of the signal that reaches it is R ÷ √(R² + X²), where X is what's left of the two reactances:

StationNet reactanceReaches the receiver
1 MHzabout −j1.6 kΩabout 3 %
10 MHzabout 0nearly all
30 MHzabout +j420 Ωabout 12 %

Live experiment

Slide the peak along the band

A 2.5 µH coil and a capacitor sit in series between the generator and a 50 Ω receiver, with stations on 1, 3, 10 and 30 MHz. Turn the capacitor from 1 nF down to 10 pF and the pass band slides from 3 MHz up past 30. At about 100 pF the 10 MHz station comes through whole.

Try it yourself: free lesson

“Select a band” is lesson 1 of 6 in Carrier Cove, Signals & Wireless (RF) World 1. Free with an account. It’s open as soon as you sign up.

Tuning

Frequency goes as 1 ÷ √C, so the capacitor is the tuning knob. With 1 nF the same coil peaks near 3.2 MHz; to move up to 10 MHz, about 3.2 times higher, you need about a tenth of the capacitance. Old radios did this with a variable capacitor on the dial.

How sharp the peak is depends on its Q. Here Q = √(L ÷ C) ÷ R = 158 ÷ 50, about 3, so the pass band is a few megahertz wide: enough to separate stations at 1, 10 and 30 MHz, not neighbours 100 kHz apart.

Free lesson

Now build it yourself

Each lesson comes in three short parts: see the idea, try it on a live board, then build it yourself, with quick checks as you go.

Try it yourself: free lesson

“Select a band” is lesson 1 of 6 in Carrier Cove, Signals & Wireless (RF) World 1. Free with an account. It’s open as soon as you sign up.

Or start from the very first lesson, no account needed

Work it out

Practice questions

Three quick questions from the lessons. Pick an answer to check it.

  1. Question 1 of 3At 10 MHz a 2.5 µH coil is +j157 Ω and a 100 pF capacitor about −j159 Ω. In series they add to…
    Show the answer

    Answer: About 0 Ω: the pair is a straight wire. Inductive and capacitive reactances have opposite signs. Equal and opposite, they cancel, and the only thing left in the loop is the load.

    • Why not “316 Ω”? Adding the sizes ignores their signs. A coil's +j and a capacitor's −j pull in opposite directions.
    • Why not “−159 Ω”? That's the capacitor alone. The coil's +j157 Ω cancels nearly all of it.
    • Why not “157 Ω”? That's the coil alone. The capacitor's −j159 Ω cancels it.
  2. Question 2 of 3To move the pass band from 3 MHz up to 10 MHz with the same coil, the capacitor must get…
    Show the answer

    Answer: Smaller: about a tenth. f goes as 1 ÷ √C. About 3.2 times the frequency needs about a tenth of the capacitance (3.2² ≈ 10): 1 nF down to about 100 pF.

    • Why not “Bigger”? More capacitance lowers the resonant frequency, moving the peak down, not up.
    • Why not “The same”? With the same coil and capacitor the peak stays where it is, near 3 MHz.
    • Why not “Removed”? Without the capacitor nothing cancels the coil, so there's no peak at all, just a coil blocking the high frequencies.
  3. Question 3 of 3The bin's capacitor is 1 nF. For 10 MHz with the 2.5 µH coil you set it to…
    Show the answer

    Answer: About 100 pF. C = 1 ÷ (4π² × (10⁷)² × 2.5 × 10⁻⁶) ≈ 1.0 × 10⁻¹⁰ F, which is 100 pF.

    • Why not “10 nF”? More capacitance moves the peak down, to about 1 MHz. 10 MHz needs less.
    • Why not “1 µF”? 1 µF with 2.5 µH resonates near 100 kHz, far below 10 MHz.
    • Why not “Leave it”? 1 nF with 2.5 µH resonates near 3 MHz, not 10.
Keep practising: free lesson

“Select a band” is lesson 1 of 6 in Carrier Cove, Signals & Wireless (RF) World 1. Free with an account. It’s open as soon as you sign up.

Questions people ask

What is the difference between a series and a parallel LC filter?

A series LC placed in the signal's path is nearly a short at resonance, so that frequency passes and others are blocked. A parallel LC, a tank, is nearly an open circuit at resonance; placed from the signal to ground, it lets that frequency through and shorts the others away. Both pick out one frequency.

How do I make the pass band narrower?

Raise the Q. For a series LC driving a load R, Q = √(L ÷ C) ÷ R, and the bandwidth is roughly the centre frequency divided by Q. A bigger coil and a smaller capacitor for the same frequency, or a lower-resistance load, make it sharper.

How do you tune an LC filter to a different station?

Change L or C. Old radios turned a variable capacitor. Because the frequency goes as 1 ÷ √C, moving up by about 3.2 times needs a tenth of the capacitance.

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